Epistemology
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Bott periodicity, Hamiltonians, Bott periodicity for octonion maniacs, Modeling the self, Lie algebra decomposition Quantum Symmetries
Strategy My strategy is to
And then further
Ideas
The Hilbert space Our Hilbert space has a basis which includes a vacuum state {$|0\rangle$}, {$L$} single particle states {$|1\rangle,\;\dots\;,|L\rangle$}, {$L$} single hole states {$|2\rangle|3\rangle\cdots|L\rangle,\dots,|1\rangle|2\rangle\cdots|L-1\rangle$} and a fully filled state {$|1\rangle|2\rangle\cdots|L\rangle$}. This is understood within a larger Hilbert space with states corresponding to {$2$} through {$L-2$} particles but these do not interest us. Creation {$\psi_i^\dagger$} and annihilation {$\psi_i$} operators act on these states. We need them to act in pairs so that we respect the grading. These operators anticommute whereby {$\psi_i\psi_j=-\psi_j\psi_i, \psi_i^\dagger\psi_j^\dagger=-\psi_j^\dagger\psi_i^\dagger$} and also {$\psi_i\psi_j^\dagger = -\psi_j^\dagger\psi_i$} when {$i\neq j$} but {$\psi_i\psi_i^\dagger + \psi_i^\dagger\psi_i = 1$}. These operators are collected into a row vector {$\Psi^\dagger=[\psi_1^\dagger,\dots,\psi_L^\dagger]$} and a column vector {$\Psi=[\psi_1,\dots,\psi_L]^T$}. An {$L\times L$} unitary matrix can act on them. Our Hamiltonians look like {$\mathscr{H}=\Psi^\dagger\mathbf{H}\Psi=\sum_{1\leq i,j\leq L}H_{i,j}\psi_i^\dagger \psi_j$}. Here we may need to expand this to include the hole states and perhaps the vacuum state and the fully filled state. The fact that the Hamiltonian is Hermitian means that {$H_{j,i}=H_{i,j}^*$}. A symmetry operation {$\mathscr{U}$} is defined on the Hilbert space, and in particular, on the single particle states so that {$|\langle i'|j'\rangle| = |\langle i|j\rangle| $} where {$|i'\rangle=\mathscr{U}|i\rangle, |j'\rangle=\mathscr{U}|j\rangle$}. A symmetry operation can be understood to act on the operator {$\Psi^\dagger$} whose {$L$} components construct the Hilbert space. The operator {$\mathbb{i}\mathscr{I}$} can be understood to act on these components by multiplying them by {$i$}. Then we can distinguish whether {$\mathscr{U}$} is linear {$\mathscr{U}(\mathbb{i}\mathscr{I})\mathscr{U}^{-1}=\mathbb{i}\mathscr{I}$} or antilinear {$\mathscr{U}(\mathbb{i}\mathscr{I})\mathscr{U}^{-1}=-\mathbb{i}\mathscr{I}$}. Our symmetry operations have four kinds of constructions {$\breve{H}_{ij}=$}
For the transposing symmetry operations we furthermore want {$-\breve{\mathbf{H}}_{ij}^T$} yielding
Wigner's theorem Wigner's theorem is the grounds for focusing on unitary and antiunitary transformations.
Proof of Wigner's theorem
Key to the proof {$|\psi\rangle=\sum_j c_j|\psi_j\rangle, |\psi'\rangle=\sum_jc_j\psi_j'$} {$|c_j|^2=|c_j'|^2$} because {$|\langle\psi_j|\psi\rangle|^2=|\langle u\psi_j|\overline{\psi}\rangle |^2$} {$|c_j+c_1|^2=|c_j'+c_1'|^2$} {$|1 + \frac{c_1}{c_j}|^2=|1+\frac{c_1'}{c_j'}|^2$} {$c'_j=c_je^{i\theta_j},c_1'=c_1e^{i\theta_1}, \frac{c_1'}{c_j'}=\frac{c_1}{c_j}e^{i(\theta_1-\theta_j)}$} and let {$\beta=\theta_1-\theta_j$} {$\frac{c_1}{c_j}=e^{i\alpha}$} {$|1+e^{i\alpha}|^2=|1+e^{i(\alpha + \beta)}|^2$} {$(1 +\cos\alpha)^2+\sin^2\alpha = (1+\cos (\alpha + \beta))^2+\sin^2(\alpha + \beta)$} {$1+2\cos\alpha = 1+2\cos(\alpha+\beta)$} {$\cos\alpha=\cos (\alpha + \beta)$} means {$\textrm{Re}\frac{c_1}{c_j}=\textrm{Re}\frac{c_1'}{c_j'}$} and implies {$\beta=0+2\pi$} unitary or {$\beta=-2\alpha + 2\pi$} antiunitary {$\sin\alpha = -\sin(-\alpha)$} means {$\textrm{Im}\frac{c_1}{c_j}=\pm\textrm{Im}\frac{c_1'}{c_j'}$} Usual and transposing symmetries Another foundation is the notion of transposing symmetry, which takes particles to holes and vice versa. The holes may be anti-particles. Usual symmetries fix the graded space {$\mathscr{U}_{USL}(\mathcal{V}_{N_p})=\mathcal{V}_{N_p}, \forall N_p$} Usual symmetry acts on operators {$\mathscr{U}_{USL}\Psi^\dagger\mathscr{U}_{USL}^{-1}=\Psi^\dagger\mathbf{U}_{USL}$} where {$\mathbf{U}_{USL}$} is an {$L\times L$} unitary matrix that encodes the symmetry operation as {$\mathscr{U}_{USL}\psi_i^\dagger\mathscr{U}_{USL}^{-1}=\sum_{j=1}^L\psi_j^\dagger(U_{USL})_{ji}$}. These are linear symmetries {$\mathscr{U}_{USL}(i\mathscr{I}\mathscr{U}_{USL}^{-1}=i\mathscr{I}$} where {$\mathscr{U}_{USL}\psi_i^\dagger\mathscr{U}_{USL}^{-1}=\sum_{j=1}^L\psi_j^\dagger(U_{USL})_{ji}$} and antilinear symmetries Transposing symmetries Four symmetries Symmetries The symmetries are applicable to the Hamiltonian, which is the self. The self can be understood as undefined or defined absolutely, or also defined relatively, unconsciously or consciously accessible (imaginable), unconsciously or consciously inaccessible (unimaginable). If defined relatively, then it can also be defined absolutely, if both regard to accessibility and inaccessibility. 10 anti-unitary symmetries. Anti-unitary is complex conjugation times unitary. Ludwig explains quantum symmetries in terms of first quantization (wave function) and second quantization (creation {$\hat{\psi}^\dagger_i$} and annihilation {$\hat{\psi}_i$} operators). For fermions, we have the anticommutating relations {$\hat{\psi}_i\hat{\psi}^\dagger_j = -\hat{\psi}^\dagger_j\hat{\psi}_i + \delta_{ij}$} and also {$\hat{\psi}_i\hat{\psi}_j = -\hat{\psi}_j\hat{\psi}_i, \hat{\psi}^\dagger_i\hat{\psi}^\dagger_j = -\hat{\psi}^\dagger_j\hat{\psi}^\dagger_i$}. Here the creation vector {$\hat{\psi}^\dagger=[\hat{\psi}^\dagger_1,\hat{\psi}^\dagger_2,\dots,\hat{\psi}^\dagger_n]$} is a row vector, and the annihilation vector {$\hat{\psi}=[\hat{\psi}_1,\hat{\psi}_2,\dots,\hat{\psi}_n]^T$} is a column vector. The second quantized Hamiltonian is {$\hat{H}=\sum_{A,B}\hat{\psi}^\dagger_{A}H_{A,B}\hat{\psi}_B=\hat{\psi}^\dagger H\hat{\psi}$} Here the labels {$A,B$} refer to the {$N$} states (or lattice sites which may be distinguished by extra information such as spin). The Hamiltonian {$H_{A,B}$} is a matrix of numbers, called the first quantization (or single-particle) Hamiltonian. We are interested in large {$N>>1$}, the thermodynamic limit. Suppose that the Hamiltonian {$H_{A,B}$} is invariant under a group {$G_0$} of symmetries. There exist a representation of {$G$} in terms of {$N\times N$} unitary matrices {$U$}. Unitary means that {$U=U^\dagger$}. These matrices commute with the first quantized Hamiltonian. {$UH=HU$} means that {$UHU\dagger=H$}. In terms of second quantization, this corresponds to operators {$\hat{U}$} acting on the Fermion Fock space as follows.
The operators {$\hat{\mathcal{U}}$} and {$\hat{H}$} commute: {$\hat{\mathcal{U}}\hat{H}\hat{\mathcal{U}}^{-1}=\hat{H}$} Can I show this? Consider {$\hat{\mathcal{U}}\hat{H} = \hat{\mathcal{U}}\hat{\psi}^\dagger H\hat{\psi}$} Three symmetries Given the annihilation operator {$\Psi=[\psi_1, \dots, \psi_L]^T$} and creation operator {$\Psi^{\dagger}=[\psi_1^\dagger,\dots,\psi_L^\dagger]$}, we may apply a usual symmetry operator {$\mathit{U}_{USL}\Psi^\dagger\mathscr{U}_{USL}^{-1}=\Psi^\dagger\mathbf{U}_{USL}$} or a transposing symmetry operator {$\mathit{U}_{TRN}\Psi^\dagger\mathscr{U}_{TRN}^{-1}=\Psi\mathbf{U}_{USL}^*$}. We get four kinds of operator (linear or antilinear vs. usual or transposing). We can show that the operators square to {$+1$} and possibly {$-1$} but note that the relationships for the related unitary matrices are more subtle because they depend on what happens when the matrix is moved outside of the conjugation by the symmetry operator.
Note that {$\mathscr{S}=\mathscr{T}\mathscr{C}$} and {$\mathscr{S}^2=\mathscr{I}$}. This means {$\mathscr{T}\mathscr{C}\mathscr{T}\mathscr{C}=\mathscr{I}$} and so {$\mathscr{I}=\mathscr{T}^2\mathscr{T}^{-1}\mathscr{C}\mathscr{T}\mathscr{C}^{-1}\mathscr{C}^2=T\mathscr{T}^{-1}\mathscr{C}\mathscr{T}\mathscr{C}^{-1}C$}. Then {$T^{-1}C^{-1}=\mathscr{T}^{-1}\mathscr{C}\mathscr{T}\mathscr{C}^{-1}=TC$} bęcause {$T,C\in\{-1,+1\}$}. Thus {$\mathscr{C}\mathscr{T}=\mathscr{T}\mathscr{C}TC$} and we can have {$T=C$} (if {$\mathscr{T}$} and {$\mathscr{C}$} commute) or {$T=-C$} (if they anticommute). In squaring the operators, note that for charge conjugation, we have a transposing operation. If {$L$} is even, then we consider {$N_P=L/2-1$} to get {$e^{i2\theta}=1$}. Otherwise, if {$L$} is odd, then this operator must square to {$+1$}.
Time reversal Time reversal is a feature of the time-evolution operator {$\hat{\mathcal{U}}(t)=e^{itH}$} which relates the Lie algebra and the Lie group. We have {$\hat{\mathcal{T}}\hat{\mathcal{U}}(t)\hat{\mathcal{T}}^{ž1}=\hat{\mathcal{U}}(-t)$}. {$T$} is (antilinear? anticommuting, ...?) so it must contain the final linear complex structure {$J_k$}, the one that anticommutes with the elements of {$\frak{m}_k$} whereas the previous {$J_1, \dots J_{k-1}$} commute. Charge conjugation {$C$} is based on {$J_2$} because... The restrictions are based on {$J_1$} grouped with final pairs yielding {$J_1J_2J_3, J_1J_4J_5, J_1J_6J_7$} which one short of the anticommuting linear complex structure. Sublattice symmetry {$\mathbf{U}_S$} The sublattice symmetry {$1_{p,q}H1_{p,q}=-H$}. The left hand side "conjugates" the matrix by setting its two off-diagonal matrices to negative, which is the same as converting the whole matrix to its negative. This means that the diagonal blocks are zero, which we see whenever we have all three symmetries. Whereas for a single symmetry we can have nonzero diagonal blocks, even in the case of {$H^*=-H$} because here the conjugation takes place algebraically. The sublattice symmetry {$\mathbf{U}_S$} has eigenvalues restricted to {$\pm 1$} thus can be written at {$\mathbf{1}_{p,q}$}. Applying the symmetry (by seeing what commutes with operator {$iJ_1$}) breaks up the space into two subspaces. And letting go of the symmetry (by seeing what commutes with a mutually anticommmuting operator {$iJ_2$}) has the subspaces be of the same size and contain the same information. This relates to the symmetry of counting. There is a distinction between counting forwards and backwards and then the two directions have to be the same size. Similarly, we can think in terms of creation and annihilation operators. In the real case, with each new operator {$J_i$}, the sublattice symmetry is either arising or disappearing. And when it arises, it is bringing together time reversal {$\mathbf{U}_T$} and charge conjugation {$\mathbf{U}_C$} in one of four ways that the periodicity cycles through. The sublattice symmetry {$S$}
The sublattice symmetry is important when there is a double symmetry, involving both {$C$} and {$T$}, thus a triple symmetry. Note that {$\mathbf{U}_T\mathbf{U}_T^*=\mathbf{1}$}, {$\mathbf{U}_C\mathbf{U}_C^*=\mathbf{1}$}, whereas {$\mathbf{U}_S\mathbf{U}_S=\mathbf{1}$}. We have {$\mathbf{U}_S=\mathbf{U}_T\mathbf{U}_C^*$} but also, taking inverses, and using the equations above to calculate those inverses, we have {$\mathbf{U}_S=\mathbf{U}_C\mathbf{U}_T^*$}. Conjugation There are two kinds of conjugation. Algebraically, {$H^*$} indicates an change in the disposition of the self, who we identify with, as regards (the self as being) stepping in or (the self as context) stepping out. But the Hamiltonian is a Hermitian matrix so this is the same as taking the transpose. Taking the transpose changes the relationship with the context, whether the self acts on the context or the context acts on the self. Whereas the operation {$1_{p,q}H1_{p,q}$} switches the off-diagonal to negative. This changes our internal self-organization in terms of the relationship between particles and holes, which is known and unknown, switching that. Origins of Bases Conjugate transpose of {$M$} means that the action of {$M$} on one side (to the right) is now understood on the other side (to the left). And since we are dealing with complex matrices, typically unitary matrices, the conjugation is what algebraically balances this switching of sides. For the conjugate is what balances a complex number so that it can have a norm, as with {$cc*=c*c=|c|$}. The conjugate transpose replace yourself acting upon another with another acting likewise upon you. In the Hermitian case, they are both the same. Sublattice symmetry {$\mathbf{U}_S=\mathbf{1}_{p,q}$} Sublattice symmetry is transposing antilinear. It maps particles to holes and vice versa. In the q-dimensional sublattice, in the human subspace, it maps particles to negative holes, where negative indicates the conscious, thus the unknown. The sublattice symmetry establishes an absolute frame by which the self is absolutely defined. It distinguishes between the undefined, given by eigenvalues {$+1$}, and the the defined, given by eigenvalues {$-1$}. The defined distinguishes the defined undefined {$+1$} and the defined defined {$-1$}, mapping the one to the other, in what is defined. Regarding what is undefined, it maps the defined undefined to the defined undefined, and similarly with the defined defined. When we go from the absolutely defined back to the undefined, then the dimensions, {$p$} for the undefined and {$q$} for the defined, have to match. This absolute frame establishes the meaning of the real and purely imaginary numbers within the complex numbers. The real numbers describe what is undefined, and the purely imaginary numbers describe what is defined, distinguishing the defined undefined and the defined defined. Sublattice symmetry is transposing antilinear. Consider change of basis {$\tilde{\Psi}^\dagger=\Psi^\dagger \mathbf{R}$} where {$\mathbf{R}$} is unitary, {$\mathbf{R}\mathbf{R}^\dagger = 1$} Given {$\mathscr{S}\Psi^\dagger\mathscr{S}^{-1}=\Psi^T\mathbf{U}_S^*$} and {$\mathscr{S}\tilde{\Psi}^\dagger\mathscr{S}^{-1}=\tilde{\Psi}^T\tilde{\mathbf{U}}_S^*$} {$\mathscr{S}(\Psi^\dagger\mathbf{R})\mathscr{S}^{-1}=(\Psi^T\mathbf{R}^*)\tilde{\mathbf{U}}_S^*$} by substitution of {$\tilde{\Psi}^T=\Psi^TR^*$} {$\mathscr{S}\Psi^\dagger\mathscr{S}^{-1}\mathbf{R}^*=\Psi^T\mathbf{R}^*\tilde{\mathbf{U}}_S^*$} by antilinearity {$\Psi^T\mathbf{U}_S^* = \Psi^T\mathbf{R}^*\tilde{\mathbf{U}}_S^*\mathbf{R}^T$} {$\mathbf{U}_S^* = \mathbf{R}^*\tilde{\mathbf{U}}_S^*\mathbf{R}^T$} {$\mathbf{U}_S=\mathbf{R}\tilde{\mathbf{U}}_S\mathbf{R}^\dagger$} Time reversal Time reversal is usual antilinear. Consider change of basis {$\tilde{\Psi}^\dagger=\Psi^\dagger \mathbf{R}$} where {$\mathbf{R}$} is unitary, {$\mathbf{R}\mathbf{R}^\dagger = 1$} Given {$\mathscr{T}\Psi^\dagger\mathscr{T}^{-1}=\Psi^\dagger\mathbf{U}_T$} and {$\mathscr{T}\tilde{\Psi}^\dagger\mathscr{T}^{-1}=\tilde{\Psi}^\dagger\tilde{\mathbf{U}}_T$} {$\mathscr{T}(\Psi^\dagger\mathbf{R})\mathscr{T}^{-1}=(\Psi^\dagger\mathbf{R})\tilde{\mathbf{U}}_T$} by substitution {$\mathscr{T}\Psi^\dagger\mathscr{T}^{-1}\mathbf{R}^*=\Psi^\dagger\mathbf{R}\tilde{\mathbf{U}}_T$} by antilinearity {$\mathscr{T}\Psi^\dagger\mathscr{T}^{-1}$}{$ =\Psi^\dagger\mathbf{R}\tilde{\mathbf{U}}_T{\mathbf{R}^{-1}}^*$}{$= \Psi^\dagger\mathbf{R}\tilde{\mathbf{U}}_T{\mathbf{R}^\dagger}^*$}{$=\Psi^\dagger\mathbf{R}\tilde{\mathbf{U}}_T\mathbf{R}^T$} {$\Psi^\dagger\mathbf{U}_T=\Psi^\dagger\mathbf{R}\tilde{\mathbf{U}}_T\mathbf{R}^T$} {$\mathbf{U}_T=\mathbf{R}\tilde{\mathbf{U}}_T\mathbf{R}^T$} Charge conjugation Charge conjugation is transposing linear. Consider change of basis {$\tilde{\Psi}^\dagger=\Psi^\dagger \mathbf{R}$} where {$\mathbf{R}$} is unitary, {$\mathbf{R}\mathbf{R}^\dagger = 1$} Given {$\mathscr{C}\Psi^\dagger\mathscr{C}^{-1}=\Psi^T\mathbf{U}_C^*$} and {$\mathscr{C}\tilde{\Psi}^\dagger\mathscr{C}^{-1}=\tilde{\Psi}^T\tilde{\mathbf{U}}_C^*$} {$\mathscr{C}(\Psi^\dagger\mathbf{R})\mathscr{C}^{-1}=(\Psi^T\mathbf{R}^*)\tilde{\mathbf{U}}_C^*$} by substitution of {$\tilde{\Psi}^T=\Psi^TR^*$} {$\mathscr{C}\Psi^\dagger\mathscr{C}^{-1}\mathbf{R}=\psi^T\mathbf{R}^*\tilde{\mathbf{U}}_C^*$} by linearity and by tranposition {$\mathscr{C}\Psi^\dagger\mathscr{C}^{-1}=\Psi^T\mathbf{R}^*\tilde{\mathbf{U}}_C^*\mathbf{R}^{-1}$} {$\Psi^T\mathbf{U}_C^*=\Psi^T\mathbf{R}^*\tilde{\mathbf{U}}_C^*\mathbf{R}^\dagger$} {$\mathbf{U}_C^*=\mathbf{R}^*\tilde{\mathbf{U}}_C^*\mathbf{R}^\dagger$} {$\mathbf{U}_C=\mathbf{R}\tilde{\mathbf{U}}_C\mathbf{R}^T$} Table of Interpretations Complex Bott periodicity is based on {$H$} and describes God as the reference for an absolute frame. God is frameless. He takes on an absolute frame. An absolute frame of an absolute frame is framelessness. Framelessness is without a basis, and the absolute frame provides an absolute basis. Real Bott periodicity is based on {$H^*$} and describes human as the reference for a relative frame. Charge conjugation is the symmetry of the inaccessible, the unimaginable, as when the Hamiltonian is purely imaginary. Time reversal is the symmetry of the accessible, the imaginable, as when the Hamiltonian is purely real. These can be either unconscious (squaring to {$+1$}) or conscious (squaring to {$-1$}). The basis is chosen relative to the symmetry, when it is alone, and relative to the absolute frame, when there are all three symmetries, which opens up a complementary symmetry. The absolute frame allows us to switch from the imaginable to the unimaginable or vice versa. Alternating, back and forth, yields the divisions of everything. For accessibility, imaginability, the reference point is the unitary group, just as with God. For inaccessibility, unimaginability, the reference points are, unconsciously, the orthogonal group, and consciously, the symplectic group.
Walking through the Hamiltonians with complex Bott periodicity This describes the relationship between having no subsystem (God) and having a subsystem (human, as opposed to God). The Hamiltonians express what is left free by the symmetries. They are the freedom of the self. They express how the freedom expresses the constraints. The freedom is channeled in perspectives. Twofold periodicity is driven by the symmetry {$SHS^{-1}=-H$} which acts on {$H$} directly, thus bringing out the symmetry of the Hermitian matrix, yielding a unitary matrix upon exponentiation {$e^{iH}$}. God There is no additional symmetry but there is simply the fact that {$H=H^\dagger$} is Hermitian. Human Here we are working with {$U(2r)$} and we allow for complex numbers. We have operators {$K_j=iJ_j$} with {$K_j^2=\mathbb{I}$} splitting the complex vector space {$\mathbb{C}^{2r}$} into two components with eigenvalues {$+1$} and {$-1$} which can be of different size. In particular, {$J_1$} can be a diagonal matrix with {$p$} entries {$i$} and {$q$} entries {$-i$}. Then {$U(p)\times U(q)$} is the subset of {$U(p+q)$} which commutes with {$J_1$}. These are matrices with blocks {$u_1$} and {$u_2$} on the diagonal. The matrices that anticommute with {$J_1$} have blocks on the off-diagonal and they express {$\frak{u}$}{$(2r)\backslash\frak{u}$}{$(r)\oplus\frak{u}$}{$(r)$}. We usually write {$J_1=\begin{pmatrix} & -1 \\ 1 & \\ \end{pmatrix}$} but this would force the eigenspaces of {$iJ_1$} to be of equal size. Instead, since we are working with a complex vector space, we can write: {$J_1=\begin{pmatrix} i & \\ & -i \\ \end{pmatrix}, J_2=\begin{pmatrix} & i \\ i & \\ \end{pmatrix}$} For {$J_1$}, the number of {$i$} and the number of {$-i$} on the diagonal can be different, {$p$] and {$q$}, respectively, with consequences for {$iJ_1$}. In order to define {$J_2$}, we need {$p=q$}. {$J_2$} is an isometry of {$V_+$} and {$V_-$} and it squares to {$-1$}. {$J_1$} and {$J_2$} anticommute. Consider {$\begin{pmatrix} u_1 & \\ & u_2 \\ \end{pmatrix}\begin{pmatrix} & i \\ i & \\ \end{pmatrix}=\begin{pmatrix} & iu_1 \\ iu_2 & \\ \end{pmatrix}, \begin{pmatrix} & i \\ i & \\ \end{pmatrix}\begin{pmatrix} u_1 & \\ & u_2 \\ \end{pmatrix}=\begin{pmatrix} & iu_2 \\ iu_1 & \\ \end{pmatrix}$} Commutation implies that {$u_1=u_2$} and so we are left with {$U(n)$}. Anticommutation implies {$u_1=-u_2$}. In either case, the resulting matrices are isomorphic to {$U(n)$} {$\begin{pmatrix} u & \\ & u \\ \end{pmatrix}, \; \begin{pmatrix} u & \\ & -u \\ \end{pmatrix}$} In terms of the corresponding Lie algebras, this simply means that we are decomposing {$\frak{u}$}{$(n)\oplus\frak{u}$}{$(n)$}. There is the symmetry {$1_{p,q}H1_{p,q}=-H$} where {$S=1_{p,q}$}. {$H=-1_{p,q}H1_{p,q}=-\begin{pmatrix} 1_p & \\ & -1_q \\ \end{pmatrix}\begin{pmatrix} h_{aa} & h_{ab} \\ h_{ba} & h_{bb} \\ \end{pmatrix}\begin{pmatrix} 1_p & \\ & -1_q \\ \end{pmatrix} $} {$=-\begin{pmatrix} h_{aa} & h_{ab} \\ -h_{ba} & -h_{bb} \\ \end{pmatrix}\begin{pmatrix} 1_p & \\ & -1_q \\ \end{pmatrix} $} {$=-\begin{pmatrix} h_{aa} & -h_{ab} \\ -h_{ba} & h_{bb} \\ \end{pmatrix}$} {$=\begin{pmatrix} -h_{aa} & h_{ab} \\ h_{ba} & -h_{bb} \\ \end{pmatrix}$} {$h_{aa}=0, h_{bb}=0$}. Also, {$H$} is Hermitian implies {$h_{ba}=h_{ab}^\dagger$} {$H=\begin{pmatrix} & h_{ab} \\ h_{ab}^\dagger & \\ \end{pmatrix}$} Note that we are missing hermitian matrices of the form {$M=\begin{pmatrix} h_{aa} & \\ & h_{bb} \\ \end{pmatrix}$}, where {$iM$} generate the Lie algebra {$\frak{u}(\textrm{p})\oplus\frak{u}(\textrm{q})$}. Thus {$i\mathcal{H}$} is given by {$\frak{u}(\textrm{p+q})\backslash\frak{u}(\textrm{p})\oplus\frak{u}(\textrm{q})$}. Note that we may have {$p\neq q$} and so this is not the same as complex conjugation. In continuing, we are identifying {$h_pq=h_pq^\dagger$}, which we already knew. All that we are truly doing is insisting that {$q=p$}. Whereas all that we did to get here was to impose a symmetry that distinguished between {$V_+$} and {$V_-$}, thus {$p$} and {$q$} accordingly. It seems that at any point we can adjust the overall dimension to be what we want it to be, at our convenience. This is similar to choosing the degree of precision, coarse or fine, and it doesn't affect our internal reality, which is given by our perspectives {$J_k$}, the structure of our Hamiltonian, its symmetries, and any related isometries. God and human are distinguished upon distinguishing divine {$V_+$} and human {$V_-$}, where humans can swap back and forth between knowing and not knowing, upon reflection. What then matters is their relationship as given by the off-diagonal matrices. Then human and God are reunited upon matching their dimensions, in which case the distinction and the relationship disappear. In going between the two states, note that there is a significant difference between {$\frak{u}$}{$(n)$} and {$\frak{u}$}{$(p)\oplus\frak{u}$}{$(q)$}. The quotient {$U(2n)/U(p)\times U(q)$} is the complex Grassmannian. Whereas qualitatively not much difference in the respective Hamiltonians, the complement {$\frak{m}_0$} and {$\frak{m}_1$}, as they are basically the same, just different dimension. Importantly, from the Hamiltonian point of view, the key difference is in the complement, and also in the constraints on the number - are there two eigenspaces - and are they forced to be equal in size? Complex Bott periodicity models how we humans can be free of ourselves, frameless, by living through God. Walking through the Hamiltonians with real Bott periodicity Here there is always assumed to be a subsystem. We go back and forth between having two symmetries or just one. {$T:H^*\rightarrow H$} sends {$a-bi$} to {$a+bi$} swapping imaginaries. {$C:H^*\rightarrow -H$} sends {$a-bi$} to {$-a-bi$} swapping reals. Eightfold periodicity is driven by the conjugate {$H*$}, through two symmetries {$TH^*T^{-1}=H$} and {$CH^*C^{-1}=-H$}. Note that {$T$} is an ordinary symmetry, with no concept of holes or particles, whereas {$C$} is a transposing symmetry, with a concept of particles and holes. We walk through the Bott clock alternating between having both symmetries or having just one of them. Note that we start and end at {$C$}. Consider what it means to have unmarked-marked opposites {$H$} and {$-H$} and twin unmarked-unmarked opposites, imaginary numbers {$i$} and {$j$} with {$\bar{i}=j$} and {$\bar{j}=i$}. Note that known (raw, direct, unreflected experience) and unknown (indirect, reflected) are unmarked and marked. Note that {$H$} and {$H^\dagger$} are twin opposites. One is the context of the other. But neither is intrinsically primary, as regards the underlying norm. However, one is then chosen as the inhabited one, the resident one, the being. Note also, however, that the dual vector space has a notion of functional which is secondary and brings in a map into the field, which is a marker, making the dual vector space marked. Note also that {$+1$} and {$-1$} are unmarked and marked only as the secondary operation (multiplication in a ring). In an additive group, such as {$\mathbb{Z}$} they are the same, they both serve as generators, because the identity is zero. Note also the difference between zero and a blank space, as opposites, here marked and unmarked. The Hamiltonian describes the limits on what we can imagine, what we can access. Real describes what is accessible to us, and imaginary what is unaccessible, beyond what we can imagine. We start with the Hamiltonian being entirely imaginary, establishing the nullsome. With the sixsome, everything is real, giving the extent of our imagination. So I should look for a process by which the Hamiltonian becomes more accessible, more real. Charge conjugation describes what is unaccessible, imaginary, and time reversal describes what is accessible, real. What drives the Bott clock is that the bases underling the symmetries are changing. When there is a single symmetry, then it can be expressed straightforwardly as 1 or J. But when there are two symmetries, then their bases need to be written in terms of the basis for the sublattice symmetry. I need to understand how the bases change as we go around the clock, alternating between the sublattice symmetry and the individual symmetries. Going from a single symmetry to a double symmetry, the single symmetry gets embedded in an absolute context, changing its basis as necessary or not. This includes a new, complementary symmetry. Then that symmetry is considered in isolation, simplifying its basis relative to itself, then as such getting embedded in the absolute context. It is interesting that this yields new results, not going backwards. Real Bott periodicity, assuming {$H^*$}, thus real numbers - imaginability, models how humans are trapped in ourselves. Nullsome
The symmetry {$\mathbf{1_{p,q}H=-H1_{p,q}}$} can be written {$1_{p,q}H1_{p,q}= H^* = -H$}. Onesome
{$H$} and {$-H^*$} are separated, identified with going back and forth between subspaces, and real numbers are now allowed. Twosome
{$\mathbf{\begin{pmatrix} & 1_{mm} \\ -1_{mm} & \end{pmatrix}H^*=H\begin{pmatrix} & 1_{mm} \\ -1_{mm} & \end{pmatrix}}$} The symmetry can be written {$\begin{pmatrix} & -1_{mm} \\ 1_{mm} & \end{pmatrix}\mathbf{H}\begin{pmatrix} & 1_{mm} \\ -1_{mm} & \end{pmatrix}= \mathbf{H}^*$} {$\begin{pmatrix} & -1_{mm} \\ 1_{mm} & \end{pmatrix}\begin{pmatrix} h_{aa} & h_{ab} \\ h_{ba} & h_{bb} \end{pmatrix}\begin{pmatrix} & 1_{mm} \\ -1_{mm} & \end{pmatrix}= \begin{pmatrix} h_{aa}^* & h_{ab}^* \\ h_{ba}^* & h_{bb}^* \end{pmatrix}$} {$=\begin{pmatrix} -h_{ba} & -h_{bb} \\ h_{aa} & h_{ab} \end{pmatrix}\begin{pmatrix} & 1_{mm} \\ -1_{mm} & \end{pmatrix}= \begin{pmatrix} h_{bb} & -h_{ba} \\ -h_{ab} & h_{aa} \end{pmatrix} = \begin{pmatrix} h_{aa}^* & h_{ab}^* \\ h_{ba}^* & h_{bb}^* \end{pmatrix}$} Thus {$h_{bb}=h_{aa}^*, h_{ba}=-h_{ab}^*$}. Consequently, {$H=\begin{pmatrix} h_{aa} & h_{ab} \\ -h_{ab}^* & h_{aa}^* \end{pmatrix}$} The absolute space and relative space are distinguished and allowed to have self-relations. Threesome
{$H$} and {$H^\dagger$} are separated. Foursome
{$\mathbf{\begin{pmatrix} & 1_{mm} \\ -1_{mm} & \end{pmatrix}H^*=-H\begin{pmatrix} & 1_{mm} \\ -1_{mm} & \end{pmatrix}}$} The symmetry can be written {$\begin{pmatrix} & -1_{mm} \\ 1_{mm} & \end{pmatrix}\mathbf{H}\begin{pmatrix} & 1_{mm} \\ -1_{mm} & \end{pmatrix}= -\mathbf{H}^*$} {$\begin{pmatrix} & -1_{mm} \\ 1_{mm} & \end{pmatrix}\begin{pmatrix} h_{aa} & h_{ab} \\ h_{ba} & h_{bb} \end{pmatrix}\begin{pmatrix} & 1_{mm} \\ -1_{mm} & \end{pmatrix}= \begin{pmatrix} -h_{aa}^* & -h_{ab}^* \\ -h_{ba}^* & -h_{bb}^* \end{pmatrix}$} {$=\begin{pmatrix} -h_{ba} & -h_{bb} \\ h_{aa} & h_{ab} \end{pmatrix}\begin{pmatrix} & 1_{mm} \\ -1_{mm} & \end{pmatrix}= \begin{pmatrix} h_{bb} & -h_{ba} \\ -h_{ab} & h_{aa} \end{pmatrix} = \begin{pmatrix} -h_{aa}^* & -h_{ab}^* \\ -h_{ba}^* & -h_{bb}^* \end{pmatrix}$} Thus {$h_{bb}=-h_{aa}^*, h_{ba}=h_{ab}^*$}. Consequently, {$H=\begin{pmatrix} h_{aa} & h_{ab} \\ h_{ab}^* & -h_{aa}^* \end{pmatrix}$} The complementary space is allowed and united, allowing for diagonal elements. The negative sign of the bottom row has been swapped. Fivesome
The diagonal elements are made zero. Sixsome
{$\mathbf{1_{p,q}H=H1_{p,q}}$} The symmetry {$\mathbf{1_{p,q}H=H1_{p,q}}$} can be written {$1_{p,q}H1_{p,q}= H^* = H$}. The off-diagonal blocks {$h_{mm}$} and {$h_{mm}^*$} are identified and united, making them real. Sevensome
{$H$} and {$H^*$} are distinguished, and allowed to be non-square. Eightsome
{$\mathbf{1_{p,q}H=-H1_{p,q}}$} {$h_{pq}$} and {$h_{pg}^*$} are identified as negatives of each other. The negative sign of the bottom row has been swapped (from the zero onto {$h_{pq}^*$}). |